Gujarati
Hindi
4-2.Friction
hard

A force acts on a block as shown in figure. Find time when block loses contact with surface.

A

$t = 25/3 \, \sec$

B

$t = 50/3 \, \sec$

C

$t = 100/3 \, \sec$

D

$t = 50 \, \sec$

Solution

$\mathrm{N}=\mathrm{F} \sin 37^{\circ}-\mathrm{mg}$

as per given condition

When $\mathrm{N}=0 \quad \mathrm{F} \sin 37^{\circ}-\mathrm{mg}=0$

$\Rightarrow F \sin 37^{\circ}=\mathrm{mg}$

$\Rightarrow 10 t \times \frac{3}{5}=10 \times 10 \Rightarrow t=\frac{50}{3} \mathrm{s}$

Standard 11
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.